2^(x^2-5x)=(1)/(64)

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Solution for 2^(x^2-5x)=(1)/(64) equation: 



2^(x^2-5x)=(1)/(64)

We move all terms to the left:

2^(x^2-5x)-((1)/(64))=0

We add all the numbers together, and all the variables

2^(x^2-5x)-(+1/64)=0

We get rid of parentheses

2^(x^2-5x)-1/64=0

We multiply all the terms by the denominator


(2^(x^2-5x))*64-1=0

We move all terms containing x to the left, all other terms to the right

(2^(x^2-5x))*64=1

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